K Category Options and Descriptions
K02 Calibration Mode
Simple mode
0
Default
The simple calibration mode applies a formula to adjust the instantaneous flow rate:
Calibrated instantaneous flow = (K03 × uncalibrated instantaneous flow) − K04
Example 1 If the desired calibrated flow rate is half of the current displayed value, set K03 to 0.5, and leave K04 at the default value 0.
Example:
Uncalibrated instantaneous flow: 5.0 L/min
Calibrated instantaneous flow: 2.5 L/min = 0.5 × 5.0 L/min
Example 2 For multi-point calibration requiring the addition or subtraction of a constant to maintain linearity:
10
4
20
9
Set K03 to 0.5 and K04 to 1.0.
4 L/min = 0.5 × 10 L/min − 1.0
9 L/min = 0.5 × 20 L/min − 1.0
K03 Scale Factor A proportional adjustment to the flow rate, default is 1.0. This parameter is synchronised with Z05.
Data Type
float32
Default
1.0
Minimum
0.001
Maximum
1000.
K04 Manual Offset A fixed value is subtracted from the instantaneous flow rate according to the input. The unit matches the system setting.
Example: Entering 1.0 subtracts 1.0 from the current flow. If the original flow is 3.0, the output becomes 2.0. Default value: 0.0. This parameter functions similarly to Zero Offset but operates independently.
Data Type
float32
Default
0
Minimum
-100000
Maximum
100000
K05 Totalizer Scale (Cumulative Total Ratio) Adjusts the ratio of the amount added to the Totalizer from the calibrated instantaneous flow. It does not affect previously accumulated data. Adjustments amplify both positive and negative values.
Use case: Maintain the same instantaneous flow data while accounting for differences in cumulative values (e.g., using density to reflect weight).
Default value: 1.0.
Data Type
float32
Default
1
Minimum
0.001
Maximum
1000
Formula:
New cumulative value = Previous cumulative value + (K05 × newly added calibrated flow)
Example: If the Totalizer currently increases by 1 L/min, and the cumulative value is 100 L, to double the accumulation rate without altering the flow rate, set K05 to 2.0:
New cumulative value = 100 + 2 × 1 = 102 L
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